Solve (28-35*2^2/sqrt{37-8})^0

$$( \frac { 28 - 35 \times 2 ^ { 2 } } { \sqrt { 37 - 8 } } ) ^ { 0 }$$

Evaluate

$$1$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\left(\frac{28-35\times 4}{\sqrt{37-8}}\right)^{0}$$

Multiply 35 and 4 to get 140.

$$\left(\frac{28-140}{\sqrt{37-8}}\right)^{0}$$

Subtract 140 from 28 to get -112.

$$\left(\frac{-112}{\sqrt{37-8}}\right)^{0}$$

Subtract 8 from 37 to get 29.

$$\left(\frac{-112}{\sqrt{29}}\right)^{0}$$

Rationalize the denominator of \frac{-112}{\sqrt{29}} by multiplying numerator and denominator by \sqrt{29}.

$$\left(\frac{-112\sqrt{29}}{\left(\sqrt{29}\right)^{2}}\right)^{0}$$

The square of \sqrt{29} is 29.

$$\left(\frac{-112\sqrt{29}}{29}\right)^{0}$$

To raise \frac{-112\sqrt{29}}{29} to a power, raise both numerator and denominator to the power and then divide.

$$\frac{\left(-112\sqrt{29}\right)^{0}}{29^{0}}$$

Calculate -112\sqrt{29} to the power of 0 and get 1.

$$\frac{1}{29^{0}}$$

Calculate 29 to the power of 0 and get 1.

$$\frac{1}{1}$$

Anything divided by one gives itself.

$$1$$

Factor

$$1$$