Solve (23/12)^2-23/6+3=

$$( \frac { 23 } { 12 } ) ^ { 2 } - \frac { 23 } { 6 } + 3 =$$

Evaluate

$$\frac{409}{144}\approx 2.840277778$$

Solution Steps

Calculate \frac{23}{12} to the power of 2 and get \frac{529}{144}.

$$\frac{529}{144}-\frac{23}{6}+3$$

Least common multiple of 144 and 6 is 144. Convert \frac{529}{144} and \frac{23}{6} to fractions with denominator 144.

$$\frac{529}{144}-\frac{552}{144}+3$$

Since \frac{529}{144} and \frac{552}{144} have the same denominator, subtract them by subtracting their numerators.

$$\frac{529-552}{144}+3$$

Subtract 552 from 529 to get -23.

$$-\frac{23}{144}+3$$

Convert 3 to fraction \frac{432}{144}.

$$-\frac{23}{144}+\frac{432}{144}$$

Since -\frac{23}{144} and \frac{432}{144} have the same denominator, add them by adding their numerators.

$$\frac{-23+432}{144}$$

Add -23 and 432 to get 409.

$$\frac{409}{144}$$

Factor

$$\frac{409}{2 ^ {4} \cdot 3 ^ {2}} = 2\frac{121}{144} = 2.8402777777777777$$