Solve (21/26*13/7+1/2)div5/9

$$( \frac { 21 } { 26 } \times \frac { 13 } { 7 } + \frac { 1 } { 2 } ) \div \frac { 5 } { 9 }$$

Evaluate

$$\frac{18}{5}=3.6$$

Solution Steps

Multiply \frac{21}{26} times \frac{13}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{21\times 13}{26\times 7}+\frac{1}{2}}{\frac{5}{9}}$$

Do the multiplications in the fraction \frac{21\times 13}{26\times 7}.

$$\frac{\frac{273}{182}+\frac{1}{2}}{\frac{5}{9}}$$

Reduce the fraction \frac{273}{182} to lowest terms by extracting and canceling out 91.

$$\frac{\frac{3}{2}+\frac{1}{2}}{\frac{5}{9}}$$

Since \frac{3}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{\frac{3+1}{2}}{\frac{5}{9}}$$

Add 3 and 1 to get 4.

$$\frac{\frac{4}{2}}{\frac{5}{9}}$$

Divide 4 by 2 to get 2.

$$\frac{2}{\frac{5}{9}}$$

Divide 2 by \frac{5}{9} by multiplying 2 by the reciprocal of \frac{5}{9}.

$$2\times \frac{9}{5}$$

Express 2\times \frac{9}{5} as a single fraction.

$$\frac{2\times 9}{5}$$

Multiply 2 and 9 to get 18.

$$\frac{18}{5}$$

Factor

$$\frac{2 \cdot 3 ^ {2}}{5} = 3\frac{3}{5} = 3.6$$