Solve (20/2)*[0+0+2(16+24+22+27+35+35+30+30+22+22))]

$$( \frac { 20 } { 2 } ) \times [ 0 + 0 + 2 ( 16 + 24 + 22 + 27 + 35 + 35 + 30 + 30 + 22 + 22 ) ) ]$$

Evaluate

$$5260$$

Solution Steps

Divide 20 by 2 to get 10.

$$10\left(0+0+2\left(16+24+22+27+35+35+30+30+22+22\right)\right)$$

Add 0 and 0 to get 0.

$$10\times 2\left(16+24+22+27+35+35+30+30+22+22\right)$$

Add 16 and 24 to get 40.

$$10\times 2\left(40+22+27+35+35+30+30+22+22\right)$$

Add 40 and 22 to get 62.

$$10\times 2\left(62+27+35+35+30+30+22+22\right)$$

Add 62 and 27 to get 89.

$$10\times 2\left(89+35+35+30+30+22+22\right)$$

Add 89 and 35 to get 124.

$$10\times 2\left(124+35+30+30+22+22\right)$$

Add 124 and 35 to get 159.

$$10\times 2\left(159+30+30+22+22\right)$$

Add 159 and 30 to get 189.

$$10\times 2\left(189+30+22+22\right)$$

Add 189 and 30 to get 219.

$$10\times 2\left(219+22+22\right)$$

Add 219 and 22 to get 241.

$$10\times 2\left(241+22\right)$$

Add 241 and 22 to get 263.

$$10\times 2\times 263$$

Multiply 2 and 263 to get 526.

$$10\times 526$$

Multiply 10 and 526 to get 5260.

$$5260$$

Factor

$$2^{2}\times 5\times 263$$