Solve (2-x/4-2x+3/6)*12=

$$( \frac { 2 - x } { 4 } - \frac { 2 x + 3 } { 6 } ) \times 12 =$$

Evaluate

$$-7x$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4 and 6 is 12. Multiply \frac{2-x}{4} times \frac{3}{3}. Multiply \frac{2x+3}{6} times \frac{2}{2}.

$$\left(\frac{3\left(2-x\right)}{12}-\frac{2\left(2x+3\right)}{12}\right)\times 12$$

Since \frac{3\left(2-x\right)}{12} and \frac{2\left(2x+3\right)}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\left(2-x\right)-2\left(2x+3\right)}{12}\times 12$$

Do the multiplications in 3\left(2-x\right)-2\left(2x+3\right).

$$\frac{6-3x-4x-6}{12}\times 12$$

Combine like terms in 6-3x-4x-6.

$$\frac{-7x}{12}\times 12$$

Cancel out 12 and 12.

$$-7x$$

Expand

$$-7x$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4 and 6 is 12. Multiply \frac{2-x}{4} times \frac{3}{3}. Multiply \frac{2x+3}{6} times \frac{2}{2}.

$$\left(\frac{3\left(2-x\right)}{12}-\frac{2\left(2x+3\right)}{12}\right)\times 12$$

Since \frac{3\left(2-x\right)}{12} and \frac{2\left(2x+3\right)}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3\left(2-x\right)-2\left(2x+3\right)}{12}\times 12$$

Do the multiplications in 3\left(2-x\right)-2\left(2x+3\right).

$$\frac{6-3x-4x-6}{12}\times 12$$

Combine like terms in 6-3x-4x-6.

$$\frac{-7x}{12}\times 12$$

Cancel out 12 and 12.

$$-7x$$