Solve (2/9+4/15)-9/45=

$$( \frac { 2 } { 9 } + \frac { 4 } { 15 } ) - \frac { 9 } { 45 } =$$

Evaluate

$$\frac{13}{45}\approx 0.288888889$$

Solution Steps

Least common multiple of 9 and 15 is 45. Convert \frac{2}{9} and \frac{4}{15} to fractions with denominator 45.

$$\frac{10}{45}+\frac{12}{45}-\frac{9}{45}$$

Since \frac{10}{45} and \frac{12}{45} have the same denominator, add them by adding their numerators.

$$\frac{10+12}{45}-\frac{9}{45}$$

Add 10 and 12 to get 22.

$$\frac{22}{45}-\frac{9}{45}$$

Since \frac{22}{45} and \frac{9}{45} have the same denominator, subtract them by subtracting their numerators.

$$\frac{22-9}{45}$$

Subtract 9 from 22 to get 13.

$$\frac{13}{45}$$

Factor

$$\frac{13}{3 ^ {2} \cdot 5} = 0.28888888888888886$$