Solve (2/5+1/3)div3/45=

$$( \frac { 2 } { 5 } + \frac { 1 } { 3 } ) \div \frac { 3 } { 45 } =$$

Evaluate

$$11$$

Solution Steps

Least common multiple of 5 and 3 is 15. Convert \frac{2}{5} and \frac{1}{3} to fractions with denominator 15.

$$\frac{\frac{6}{15}+\frac{5}{15}}{\frac{3}{45}}$$

Since \frac{6}{15} and \frac{5}{15} have the same denominator, add them by adding their numerators.

$$\frac{\frac{6+5}{15}}{\frac{3}{45}}$$

Add 6 and 5 to get 11.

$$\frac{\frac{11}{15}}{\frac{3}{45}}$$

Reduce the fraction \frac{3}{45} to lowest terms by extracting and canceling out 3.

$$\frac{\frac{11}{15}}{\frac{1}{15}}$$

Divide \frac{11}{15} by \frac{1}{15} by multiplying \frac{11}{15} by the reciprocal of \frac{1}{15}.

$$\frac{11}{15}\times 15$$

Cancel out 15 and 15.

$$11$$

Factor

$$11$$