Solve (2/3-1/2)*4/9

$$( \frac { 2 } { 3 } - \frac { 1 } { 2 } ) \times \frac { 4 } { 9 }$$

Evaluate

$$\frac{2}{27}\approx 0.074074074$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{2}{3} and \frac{1}{2} to fractions with denominator 6.

$$\left(\frac{4}{6}-\frac{3}{6}\right)\times \frac{4}{9}$$

Since \frac{4}{6} and \frac{3}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-3}{6}\times \frac{4}{9}$$

Subtract 3 from 4 to get 1.

$$\frac{1}{6}\times \frac{4}{9}$$

Multiply \frac{1}{6} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 4}{6\times 9}$$

Do the multiplications in the fraction \frac{1\times 4}{6\times 9}.

$$\frac{4}{54}$$

Reduce the fraction \frac{4}{54} to lowest terms by extracting and canceling out 2.

$$\frac{2}{27}$$

Factor

$$\frac{2}{3 ^ {3}} = 0.07407407407407407$$