Solve (2/3)^2-(-1)^3-1/8

$$( \frac { 2 } { 3 } ) ^ { 2 } - ( - 1 ) ^ { 3 } - \frac { 1 } { 8 }$$

Evaluate

$$\frac{95}{72}\approx 1.319444444$$

Solution Steps

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{4}{9}-\left(-1\right)^{3}-\frac{1}{8}$$

Calculate -1 to the power of 3 and get -1.

$$\frac{4}{9}-\left(-1\right)-\frac{1}{8}$$

The opposite of -1 is 1.

$$\frac{4}{9}+1-\frac{1}{8}$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{4}{9}+\frac{9}{9}-\frac{1}{8}$$

Since \frac{4}{9} and \frac{9}{9} have the same denominator, add them by adding their numerators.

$$\frac{4+9}{9}-\frac{1}{8}$$

Add 4 and 9 to get 13.

$$\frac{13}{9}-\frac{1}{8}$$

Least common multiple of 9 and 8 is 72. Convert \frac{13}{9} and \frac{1}{8} to fractions with denominator 72.

$$\frac{104}{72}-\frac{9}{72}$$

Since \frac{104}{72} and \frac{9}{72} have the same denominator, subtract them by subtracting their numerators.

$$\frac{104-9}{72}$$

Subtract 9 from 104 to get 95.

$$\frac{95}{72}$$

Factor

$$\frac{5 \cdot 19}{2 ^ {3} \cdot 3 ^ {2}} = 1\frac{23}{72} = 1.3194444444444444$$