Solve (2/3+11/12)*1/2

$$( \frac { 2 } { 3 } + \frac { 11 } { 12 } ) \cdot \frac { 1 } { 2 }$$

Evaluate

$$\frac{19}{24}\approx 0.791666667$$

Solution Steps

Least common multiple of 3 and 12 is 12. Convert \frac{2}{3} and \frac{11}{12} to fractions with denominator 12.

$$\left(\frac{8}{12}+\frac{11}{12}\right)\times \frac{1}{2}$$

Since \frac{8}{12} and \frac{11}{12} have the same denominator, add them by adding their numerators.

$$\frac{8+11}{12}\times \frac{1}{2}$$

Add 8 and 11 to get 19.

$$\frac{19}{12}\times \frac{1}{2}$$

Multiply \frac{19}{12} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{19\times 1}{12\times 2}$$

Do the multiplications in the fraction \frac{19\times 1}{12\times 2}.

$$\frac{19}{24}$$

Factor

$$\frac{19}{2 ^ {3} \cdot 3} = 0.7916666666666666$$