Solve (2/3^2)^-2(2^2/3^3)=

$$( \frac { 2 } { 3 ^ { 2 } } ) ^ { - 2 } ( \frac { 2 ^ { 2 } } { 3 ^ { 3 } } ) =$$

Evaluate

$$3$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\left(\frac{2}{9}\right)^{-2}\times \frac{2^{2}}{3^{3}}$$

Calculate \frac{2}{9} to the power of -2 and get \frac{81}{4}.

$$\frac{81}{4}\times \frac{2^{2}}{3^{3}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{81}{4}\times \frac{4}{3^{3}}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{81}{4}\times \frac{4}{27}$$

Multiply \frac{81}{4} and \frac{4}{27} to get 3.

$$3$$

Factor

$$3$$