Solve (10/30*20/29)+(20/30*10/29)

$$( \frac { 10 } { 30 } \times \frac { 20 } { 29 } ) + ( \frac { 20 } { 30 } \times \frac { 10 } { 29 } )$$

Evaluate

$$\frac{40}{87}\approx 0.459770115$$

Solution Steps

Reduce the fraction \frac{10}{30} to lowest terms by extracting and canceling out 10.

$$\frac{1}{3}\times \frac{20}{29}+\frac{20}{30}\times \frac{10}{29}$$

Multiply \frac{1}{3} times \frac{20}{29} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 20}{3\times 29}+\frac{20}{30}\times \frac{10}{29}$$

Do the multiplications in the fraction \frac{1\times 20}{3\times 29}.

$$\frac{20}{87}+\frac{20}{30}\times \frac{10}{29}$$

Reduce the fraction \frac{20}{30} to lowest terms by extracting and canceling out 10.

$$\frac{20}{87}+\frac{2}{3}\times \frac{10}{29}$$

Multiply \frac{2}{3} times \frac{10}{29} by multiplying numerator times numerator and denominator times denominator.

$$\frac{20}{87}+\frac{2\times 10}{3\times 29}$$

Do the multiplications in the fraction \frac{2\times 10}{3\times 29}.

$$\frac{20}{87}+\frac{20}{87}$$

Since \frac{20}{87} and \frac{20}{87} have the same denominator, add them by adding their numerators.

$$\frac{20+20}{87}$$

Add 20 and 20 to get 40.

$$\frac{40}{87}$$

Factor

$$\frac{2 ^ {3} \cdot 5}{3 \cdot 29} = 0.45977011494252873$$