Solve (1/9)^-3+(1/3)^-2+(1/2)^-3

$$( \frac { 1 } { 9 } ) ^ { - 3 } + ( \frac { 1 } { 3 } ) ^ { - 2 } + ( \frac { 1 } { 2 } ) ^ { - 3 }$$

Evaluate

$$746$$

Solution Steps

Calculate \frac{1}{9} to the power of -3 and get 729.

$$729+\left(\frac{1}{3}\right)^{-2}+\left(\frac{1}{2}\right)^{-3}$$

Calculate \frac{1}{3} to the power of -2 and get 9.

$$729+9+\left(\frac{1}{2}\right)^{-3}$$

Add 729 and 9 to get 738.

$$738+\left(\frac{1}{2}\right)^{-3}$$

Calculate \frac{1}{2} to the power of -3 and get 8.

$$738+8$$

Add 738 and 8 to get 746.

$$746$$

Factor

$$2\times 373$$