Solve (1/8)^2+1/4*7/8+(7/8)^2

$$( \frac { 1 } { 8 } ) ^ { 2 } + \frac { 1 } { 4 } \times \frac { 7 } { 8 } + ( \frac { 7 } { 8 } ) ^ { 2 }$$

Evaluate

$$1$$

Solution Steps

Calculate \frac{1}{8} to the power of 2 and get \frac{1}{64}.

$$\frac{1}{64}+\frac{1}{4}\times \frac{7}{8}+\left(\frac{7}{8}\right)^{2}$$

Multiply \frac{1}{4} times \frac{7}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{64}+\frac{1\times 7}{4\times 8}+\left(\frac{7}{8}\right)^{2}$$

Do the multiplications in the fraction \frac{1\times 7}{4\times 8}.

$$\frac{1}{64}+\frac{7}{32}+\left(\frac{7}{8}\right)^{2}$$

Least common multiple of 64 and 32 is 64. Convert \frac{1}{64} and \frac{7}{32} to fractions with denominator 64.

$$\frac{1}{64}+\frac{14}{64}+\left(\frac{7}{8}\right)^{2}$$

Since \frac{1}{64} and \frac{14}{64} have the same denominator, add them by adding their numerators.

$$\frac{1+14}{64}+\left(\frac{7}{8}\right)^{2}$$

Add 1 and 14 to get 15.

$$\frac{15}{64}+\left(\frac{7}{8}\right)^{2}$$

Calculate \frac{7}{8} to the power of 2 and get \frac{49}{64}.

$$\frac{15}{64}+\frac{49}{64}$$

Since \frac{15}{64} and \frac{49}{64} have the same denominator, add them by adding their numerators.

$$\frac{15+49}{64}$$

Add 15 and 49 to get 64.

$$\frac{64}{64}$$

Divide 64 by 64 to get 1.

$$1$$

Factor

$$1$$