Solve (1/7)^4*(3/21)^2=

$$( \frac { 1 } { 7 } ) ^ { 4 } \cdot ( \frac { 3 } { 21 } ) ^ { 2 } =$$

Evaluate

$$\frac{1}{117649}\approx 0.0000085$$

Solution Steps

Calculate \frac{1}{7} to the power of 4 and get \frac{1}{2401}.

$$\frac{1}{2401}\times \left(\frac{3}{21}\right)^{2}$$

Reduce the fraction \frac{3}{21} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2401}\times \left(\frac{1}{7}\right)^{2}$$

Calculate \frac{1}{7} to the power of 2 and get \frac{1}{49}.

$$\frac{1}{2401}\times \frac{1}{49}$$

Multiply \frac{1}{2401} and \frac{1}{49} to get \frac{1}{117649}.

$$\frac{1}{117649}$$

Factor

$$\frac{1}{7 ^ {6}} = 8.499859752314087 \times 10^{-6}$$