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\frac{1}{6}x^{3}-\frac{1}{8}x-\frac{1}{7}+\frac{1}{6}x^{3}-\frac{1}{8}x+\frac{1}{7}
To find the opposite of -\frac{1}{6}x^{3}+\frac{1}{8}x-\frac{1}{7}, find the opposite of each term.
\frac{1}{3}x^{3}-\frac{1}{8}x-\frac{1}{7}-\frac{1}{8}x+\frac{1}{7}
Combine \frac{1}{6}x^{3} and \frac{1}{6}x^{3} to get \frac{1}{3}x^{3}.
\frac{1}{3}x^{3}-\frac{1}{4}x-\frac{1}{7}+\frac{1}{7}
Combine -\frac{1}{8}x and -\frac{1}{8}x to get -\frac{1}{4}x.
\frac{1}{3}x^{3}-\frac{1}{4}x
Add -\frac{1}{7} and \frac{1}{7} to get 0.
\frac{1}{6}x^{3}-\frac{1}{8}x-\frac{1}{7}+\frac{1}{6}x^{3}-\frac{1}{8}x+\frac{1}{7}
To find the opposite of -\frac{1}{6}x^{3}+\frac{1}{8}x-\frac{1}{7}, find the opposite of each term.
\frac{1}{3}x^{3}-\frac{1}{8}x-\frac{1}{7}-\frac{1}{8}x+\frac{1}{7}
Combine \frac{1}{6}x^{3} and \frac{1}{6}x^{3} to get \frac{1}{3}x^{3}.
\frac{1}{3}x^{3}-\frac{1}{4}x-\frac{1}{7}+\frac{1}{7}
Combine -\frac{1}{8}x and -\frac{1}{8}x to get -\frac{1}{4}x.
\frac{1}{3}x^{3}-\frac{1}{4}x
Add -\frac{1}{7} and \frac{1}{7} to get 0.