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\frac{1}{216}a^{3}-\frac{1}{4}a^{2}+\frac{9}{2}a-27
Use binomial theorem \left(p-q\right)^{3}=p^{3}-3p^{2}q+3pq^{2}-q^{3} to expand \left(\frac{1}{6}a-3\right)^{3}.
\frac{1}{216}a^{3}-\frac{1}{4}a^{2}+\frac{9}{2}a-27
Use binomial theorem \left(p-q\right)^{3}=p^{3}-3p^{2}q+3pq^{2}-q^{3} to expand \left(\frac{1}{6}a-3\right)^{3}.