Solve (1/6+1/4-1/8)

$$( \frac { 1 } { 6 } + \frac { 1 } { 4 } - \frac { 1 } { 8 } )$$

Evaluate

$$\frac{7}{24}\approx 0.291666667$$

Solution Steps

Least common multiple of 6 and 4 is 12. Convert \frac{1}{6} and \frac{1}{4} to fractions with denominator 12.

$$\frac{2}{12}+\frac{3}{12}-\frac{1}{8}$$

Since \frac{2}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{2+3}{12}-\frac{1}{8}$$

Add 2 and 3 to get 5.

$$\frac{5}{12}-\frac{1}{8}$$

Least common multiple of 12 and 8 is 24. Convert \frac{5}{12} and \frac{1}{8} to fractions with denominator 24.

$$\frac{10}{24}-\frac{3}{24}$$

Since \frac{10}{24} and \frac{3}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10-3}{24}$$

Subtract 3 from 10 to get 7.

$$\frac{7}{24}$$

Factor

$$\frac{7}{2 ^ {3} \cdot 3} = 0.2916666666666667$$