Solve (1/4)^3*(4/3)^2

$$( \frac { 1 } { 4 } ) ^ { 3 } \times ( \frac { 4 } { 3 } ) ^ { 2 }$$

Evaluate

$$\frac{1}{36}\approx 0.027777778$$

Solution Steps

Calculate \frac{1}{4} to the power of 3 and get \frac{1}{64}.

$$\frac{1}{64}\times \left(\frac{4}{3}\right)^{2}$$

Calculate \frac{4}{3} to the power of 2 and get \frac{16}{9}.

$$\frac{1}{64}\times \frac{16}{9}$$

Multiply \frac{1}{64} times \frac{16}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 16}{64\times 9}$$

Do the multiplications in the fraction \frac{1\times 16}{64\times 9}.

$$\frac{16}{576}$$

Reduce the fraction \frac{16}{576} to lowest terms by extracting and canceling out 16.

$$\frac{1}{36}$$

Factor

$$\frac{1}{2 ^ {2} \cdot 3 ^ {2}} = 0.027777777777777776$$