Solve (1/4+1/6-1/2)*36div(-0.6)-1^2

$$( \frac { 1 } { 4 } + \frac { 1 } { 6 } - \frac { 1 } { 2 } ) \times 36 \div ( - 0.6 ) - 1 ^ { 2 }$$

Evaluate

$$4$$

Solution Steps

Least common multiple of 4 and 6 is 12. Convert \frac{1}{4} and \frac{1}{6} to fractions with denominator 12.

$$\frac{\left(\frac{3}{12}+\frac{2}{12}-\frac{1}{2}\right)\times 36}{-0.6}-1^{2}$$

Since \frac{3}{12} and \frac{2}{12} have the same denominator, add them by adding their numerators.

$$\frac{\left(\frac{3+2}{12}-\frac{1}{2}\right)\times 36}{-0.6}-1^{2}$$

Add 3 and 2 to get 5.

$$\frac{\left(\frac{5}{12}-\frac{1}{2}\right)\times 36}{-0.6}-1^{2}$$

Least common multiple of 12 and 2 is 12. Convert \frac{5}{12} and \frac{1}{2} to fractions with denominator 12.

$$\frac{\left(\frac{5}{12}-\frac{6}{12}\right)\times 36}{-0.6}-1^{2}$$

Since \frac{5}{12} and \frac{6}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{5-6}{12}\times 36}{-0.6}-1^{2}$$

Subtract 6 from 5 to get -1.

$$\frac{-\frac{1}{12}\times 36}{-0.6}-1^{2}$$

Express -\frac{1}{12}\times 36 as a single fraction.

$$\frac{\frac{-36}{12}}{-0.6}-1^{2}$$

Divide -36 by 12 to get -3.

$$\frac{-3}{-0.6}-1^{2}$$

Expand \frac{-3}{-0.6} by multiplying both numerator and the denominator by 10.

$$\frac{-30}{-6}-1^{2}$$

Divide -30 by -6 to get 5.

$$5-1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$5-1$$

Subtract 1 from 5 to get 4.

$$4$$

Factor

$$2^{2}$$