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\left(-\frac{1}{3}\right)^{2}+\sqrt[3]{4-\frac{7}{8}}-\frac{11}{18}
Subtract \frac{2}{3} from \frac{1}{3} to get -\frac{1}{3}.
\frac{1}{9}+\sqrt[3]{4-\frac{7}{8}}-\frac{11}{18}
Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.
\frac{1}{9}+\sqrt[3]{\frac{25}{8}}-\frac{11}{18}
Subtract \frac{7}{8} from 4 to get \frac{25}{8}.
-\frac{1}{2}+\sqrt[3]{\frac{25}{8}}
Subtract \frac{11}{18} from \frac{1}{9} to get -\frac{1}{2}.