Solve (1/3+4/9*3)

$$( \frac { 1 } { 3 } + \frac { 4 } { 9 } \cdot 3 )$$

Evaluate

$$\frac{5}{3}\approx 1.666666667$$

Solution Steps

Express \frac{4}{9}\times 3 as a single fraction.

$$\frac{1}{3}+\frac{4\times 3}{9}$$

Multiply 4 and 3 to get 12.

$$\frac{1}{3}+\frac{12}{9}$$

Reduce the fraction \frac{12}{9} to lowest terms by extracting and canceling out 3.

$$\frac{1}{3}+\frac{4}{3}$$

Since \frac{1}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{1+4}{3}$$

Add 1 and 4 to get 5.

$$\frac{5}{3}$$

Factor

$$\frac{5}{3} = 1\frac{2}{3} = 1.6666666666666667$$