Solve (1/3+1/12-1/6)*(-24)

$$( \frac { 1 } { 3 } + \frac { 1 } { 12 } - \frac { 1 } { 6 } ) \times ( - 24 )$$

Evaluate

$$-6$$

Solution Steps

Least common multiple of 3 and 12 is 12. Convert \frac{1}{3} and \frac{1}{12} to fractions with denominator 12.

$$\left(\frac{4}{12}+\frac{1}{12}-\frac{1}{6}\right)\left(-24\right)$$

Since \frac{4}{12} and \frac{1}{12} have the same denominator, add them by adding their numerators.

$$\left(\frac{4+1}{12}-\frac{1}{6}\right)\left(-24\right)$$

Add 4 and 1 to get 5.

$$\left(\frac{5}{12}-\frac{1}{6}\right)\left(-24\right)$$

Least common multiple of 12 and 6 is 12. Convert \frac{5}{12} and \frac{1}{6} to fractions with denominator 12.

$$\left(\frac{5}{12}-\frac{2}{12}\right)\left(-24\right)$$

Since \frac{5}{12} and \frac{2}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-2}{12}\left(-24\right)$$

Subtract 2 from 5 to get 3.

$$\frac{3}{12}\left(-24\right)$$

Reduce the fraction \frac{3}{12} to lowest terms by extracting and canceling out 3.

$$\frac{1}{4}\left(-24\right)$$

Multiply \frac{1}{4} and -24 to get \frac{-24}{4}.

$$\frac{-24}{4}$$

Divide -24 by 4 to get -6.

$$-6$$

Factor

$$-6$$