Solve (1/2-1/3)div|-2/3|+5^0=

$$( \frac { 1 } { 2 } - \frac { 1 } { 3 } ) \div | - \frac { 2 } { 3 } | + 5 ^ { 0 } =$$

Evaluate

$$\frac{5}{4}=1.25$$

Solution Steps

Subtract \frac{1}{3} from \frac{1}{2} to get \frac{1}{6}.

$$\frac{\frac{1}{6}}{|-\frac{2}{3}|}+5^{0}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{2}{3} is \frac{2}{3}.

$$\frac{\frac{1}{6}}{\frac{2}{3}}+5^{0}$$

Divide \frac{1}{6} by \frac{2}{3} by multiplying \frac{1}{6} by the reciprocal of \frac{2}{3}.

$$\frac{1}{6}\times \frac{3}{2}+5^{0}$$

Multiply \frac{1}{6} and \frac{3}{2} to get \frac{1}{4}.

$$\frac{1}{4}+5^{0}$$

Calculate 5 to the power of 0 and get 1.

$$\frac{1}{4}+1$$

Add \frac{1}{4} and 1 to get \frac{5}{4}.

$$\frac{5}{4}$$

Factor

$$\frac{5}{2 ^ {2}} = 1\frac{1}{4} = 1.25$$