Solve (1/2)^7div(-1/2)^3

$$( \frac { 1 } { 2 } ) ^ { 7 } \div ( - \frac { 1 } { 2 } ) ^ { 3 }$$

Evaluate

$$-\frac{1}{16}=-0.0625$$

Solution Steps

Calculate \frac{1}{2} to the power of 7 and get \frac{1}{128}.

$$\frac{\frac{1}{128}}{\left(-\frac{1}{2}\right)^{3}}$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$\frac{\frac{1}{128}}{-\frac{1}{8}}$$

Divide \frac{1}{128} by -\frac{1}{8} by multiplying \frac{1}{128} by the reciprocal of -\frac{1}{8}.

$$\frac{1}{128}\left(-8\right)$$

Multiply \frac{1}{128} and -8 to get \frac{-8}{128}.

$$\frac{-8}{128}$$

Reduce the fraction \frac{-8}{128} to lowest terms by extracting and canceling out 8.

$$-\frac{1}{16}$$

Factor

$$-\frac{1}{16} = -0.0625$$