Evaluate
\frac{323}{4}-4\sqrt{15}\approx 65.258066615
Expand
\frac{323}{4} - 4 \sqrt{15} = 65.258066615
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\frac{1}{4}\left(\sqrt{3}\right)^{2}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{2}\sqrt{3}-4\sqrt{5}\right)^{2}.
\frac{1}{4}\times 3-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
The square of \sqrt{3} is 3.
\frac{3}{4}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Multiply \frac{1}{4} and 3 to get \frac{3}{4}.
\frac{3}{4}-4\sqrt{15}+16\left(\sqrt{5}\right)^{2}
To multiply \sqrt{3} and \sqrt{5}, multiply the numbers under the square root.
\frac{3}{4}-4\sqrt{15}+16\times 5
The square of \sqrt{5} is 5.
\frac{3}{4}-4\sqrt{15}+80
Multiply 16 and 5 to get 80.
\frac{323}{4}-4\sqrt{15}
Add \frac{3}{4} and 80 to get \frac{323}{4}.
\frac{1}{4}\left(\sqrt{3}\right)^{2}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{2}\sqrt{3}-4\sqrt{5}\right)^{2}.
\frac{1}{4}\times 3-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
The square of \sqrt{3} is 3.
\frac{3}{4}-4\sqrt{3}\sqrt{5}+16\left(\sqrt{5}\right)^{2}
Multiply \frac{1}{4} and 3 to get \frac{3}{4}.
\frac{3}{4}-4\sqrt{15}+16\left(\sqrt{5}\right)^{2}
To multiply \sqrt{3} and \sqrt{5}, multiply the numbers under the square root.
\frac{3}{4}-4\sqrt{15}+16\times 5
The square of \sqrt{5} is 5.
\frac{3}{4}-4\sqrt{15}+80
Multiply 16 and 5 to get 80.
\frac{323}{4}-4\sqrt{15}
Add \frac{3}{4} and 80 to get \frac{323}{4}.
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