Solve (+95/120):(-25/60)=-10/272

$$( + \frac { 95 } { 120 } ) : ( - \frac { 25 } { 60 } ) = - \frac { 10 } { 272 }$$

Verify

Solution Steps

Reduce the fraction \frac{95}{120} to lowest terms by extracting and canceling out 5.

$$\frac{\frac{19}{24}}{-\frac{25}{60}}=-\frac{10}{272}$$

Reduce the fraction \frac{25}{60} to lowest terms by extracting and canceling out 5.

$$\frac{\frac{19}{24}}{-\frac{5}{12}}=-\frac{10}{272}$$

Divide \frac{19}{24} by -\frac{5}{12} by multiplying \frac{19}{24} by the reciprocal of -\frac{5}{12}.

$$\frac{19}{24}\left(-\frac{12}{5}\right)=-\frac{10}{272}$$

Multiply \frac{19}{24} times -\frac{12}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{19\left(-12\right)}{24\times 5}=-\frac{10}{272}$$

Do the multiplications in the fraction \frac{19\left(-12\right)}{24\times 5}.

$$\frac{-228}{120}=-\frac{10}{272}$$

Reduce the fraction \frac{-228}{120} to lowest terms by extracting and canceling out 12.

$$-\frac{19}{10}=-\frac{10}{272}$$

Reduce the fraction \frac{10}{272} to lowest terms by extracting and canceling out 2.

$$-\frac{19}{10}=-\frac{5}{136}$$

Least common multiple of 10 and 136 is 680. Convert -\frac{19}{10} and -\frac{5}{136} to fractions with denominator 680.

$$-\frac{1292}{680}=-\frac{25}{680}$$

Compare -\frac{1292}{680} and -\frac{25}{680}.

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