Solve for b
b=\left(2-a\right)^{2}+3
-\left(2-a\right)\geq 0\text{ and }a\leq 2
Solve for a
a=2
b=3
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\sqrt{b-3}+|a-2|-|a-2|=-|a-2|
Subtract |a-2| from both sides of the equation.
\sqrt{b-3}=-|a-2|
Subtracting |a-2| from itself leaves 0.
b-3=\left(a-2\right)^{2}
Square both sides of the equation.
b-3-\left(-3\right)=\left(a-2\right)^{2}-\left(-3\right)
Add 3 to both sides of the equation.
b=\left(a-2\right)^{2}-\left(-3\right)
Subtracting -3 from itself leaves 0.
b=\left(a-2\right)^{2}+3
Subtract -3 from \left(a-2\right)^{2}.
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