Solve |4-8|*|7-23|*|-35+10|

$$| 4 - 8 | \cdot | 7 - 23 | \cdot | - 35 + 10 |$$

Evaluate

$$1600$$

Solution Steps

Subtract 8 from 4 to get -4.

$$|-4||7-23||-35+10|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$4|7-23||-35+10|$$

Subtract 23 from 7 to get -16.

$$4|-16||-35+10|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -16 is 16.

$$4\times 16|-35+10|$$

Multiply 4 and 16 to get 64.

$$64|-35+10|$$

Add -35 and 10 to get -25.

$$64|-25|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -25 is 25.

$$64\times 25$$

Multiply 64 and 25 to get 1600.

$$1600$$

Factor

$$2^{6}\times 5^{2}$$