Solve |3|(3-(3--9/3))+3

$$| 3 | ( 3 - ( 3 - \frac { - 9 } { 3 } ) ) + 3$$

Evaluate

$$-6$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$3\left(3-\left(3-\frac{-9}{3}\right)\right)+3$$

Divide -9 by 3 to get -3.

$$3\left(3-\left(3-\left(-3\right)\right)\right)+3$$

The opposite of -3 is 3.

$$3\left(3-\left(3+3\right)\right)+3$$

Add 3 and 3 to get 6.

$$3\left(3-6\right)+3$$

Subtract 6 from 3 to get -3.

$$3\left(-3\right)+3$$

Multiply 3 and -3 to get -9.

$$-9+3$$

Add -9 and 3 to get -6.

$$-6$$

Factor

$$-6$$