Solve |-1/3|*|36,9|+|-12,5|:2,5

$$| - \frac { 1 } { 3 } | \cdot | 36,9 | + | - 12,5 | : 2,5$$

Evaluate

$$17,3$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{1}{3} is \frac{1}{3}.

$$\frac{1}{3}|36,9|+\frac{|-12,5|}{2,5}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 36,9 is 36,9.

$$\frac{1}{3}\times 36,9+\frac{|-12,5|}{2,5}$$

Convert decimal number 36,9 to fraction \frac{369}{10}.

$$\frac{1}{3}\times \frac{369}{10}+\frac{|-12,5|}{2,5}$$

Multiply \frac{1}{3} times \frac{369}{10} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 369}{3\times 10}+\frac{|-12,5|}{2,5}$$

Do the multiplications in the fraction \frac{1\times 369}{3\times 10}.

$$\frac{369}{30}+\frac{|-12,5|}{2,5}$$

Reduce the fraction \frac{369}{30} to lowest terms by extracting and canceling out 3.

$$\frac{123}{10}+\frac{|-12,5|}{2,5}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -12,5 is 12,5.

$$\frac{123}{10}+\frac{12,5}{2,5}$$

Expand \frac{12,5}{2,5} by multiplying both numerator and the denominator by 10.

$$\frac{123}{10}+\frac{125}{25}$$

Divide 125 by 25 to get 5.

$$\frac{123}{10}+5$$

Convert 5 to fraction \frac{50}{10}.

$$\frac{123}{10}+\frac{50}{10}$$

Since \frac{123}{10} and \frac{50}{10} have the same denominator, add them by adding their numerators.

$$\frac{123+50}{10}$$

Add 123 and 50 to get 173.

$$\frac{173}{10}$$

Factor

$$\frac{173}{2 \cdot 5} = 17\frac{3}{10} = 17.3$$