Solve |-1/2|+(-1)^2019+2^-1-(pi-3)^0

$$| - \frac { 1 } { 2 } | + ( - 1 ) ^ { 2019 } + 2 ^ { - 1 } - ( \pi - 3 ) ^ { 0 }$$

Evaluate

$$-1$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{1}{2} is \frac{1}{2}.

$$\frac{1}{2}+\left(-1\right)^{2019}+2^{-1}-\left(\pi -3\right)^{0}$$

Calculate -1 to the power of 2019 and get -1.

$$\frac{1}{2}-1+2^{-1}-\left(\pi -3\right)^{0}$$

Subtract 1 from \frac{1}{2} to get -\frac{1}{2}.

$$-\frac{1}{2}+2^{-1}-\left(\pi -3\right)^{0}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$-\frac{1}{2}+\frac{1}{2}-\left(\pi -3\right)^{0}$$

Add -\frac{1}{2} and \frac{1}{2} to get 0.

$$0-\left(\pi -3\right)^{0}$$

Calculate \pi -3 to the power of 0 and get 1.

$$0-1$$

Subtract 1 from 0 to get -1.

$$-1$$

Factor

$$-1$$