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\left(x^{2}-3y^{2}\right)\left(x^{4}+3x^{2}y^{2}+9y^{4}\right)
Rewrite x^{6}-27y^{6} as \left(x^{2}\right)^{3}-\left(3y^{2}\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).