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x^{5}x^{5}+1=123x^{5}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{5}.
x^{10}+1=123x^{5}
To multiply powers of the same base, add their exponents. Add 5 and 5 to get 10.
x^{10}+1-123x^{5}=0
Subtract 123x^{5} from both sides.
t^{2}-123t+1=0
Substitute t for x^{5}.
t=\frac{-\left(-123\right)±\sqrt{\left(-123\right)^{2}-4\times 1\times 1}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -123 for b, and 1 for c in the quadratic formula.
t=\frac{123±55\sqrt{5}}{2}
Do the calculations.
t=\frac{55\sqrt{5}+123}{2} t=\frac{123-55\sqrt{5}}{2}
Solve the equation t=\frac{123±55\sqrt{5}}{2} when ± is plus and when ± is minus.
x=\sqrt[5]{\frac{55\sqrt{5}+123}{2}} x=\sqrt[5]{\frac{123-55\sqrt{5}}{2}}
Since x=t^{5}, the solutions are obtained by evaluating x=\sqrt[5]{t} for each t.