Solve x^3-x^2-x-2divx^2+x-6

$${ x }^{ 3 } - { x }^{ 2 } -x-2 \div { x }^{ 2 } +x-6$$

Evaluate

$$x^{3}-x^{2}-6-\frac{2}{x^{2}}$$

Short Solution Steps

Combine -x and x to get 0.

$$x^{3}-x^{2}-\frac{2}{x^{2}}-6$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{3}-x^{2}-6 times \frac{x^{2}}{x^{2}}.

$$\frac{\left(x^{3}-x^{2}-6\right)x^{2}}{x^{2}}-\frac{2}{x^{2}}$$

Since \frac{\left(x^{3}-x^{2}-6\right)x^{2}}{x^{2}} and \frac{2}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(x^{3}-x^{2}-6\right)x^{2}-2}{x^{2}}$$

Do the multiplications in \left(x^{3}-x^{2}-6\right)x^{2}-2.

$$\frac{x^{5}-x^{4}-6x^{2}-2}{x^{2}}$$

Factor

$$\frac{x^{5}-x^{4}-6x^{2}-2}{x^{2}}$$