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x^{2}-6.2x+0.61=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-6.2\right)±\sqrt{\left(-6.2\right)^{2}-4\times 0.61}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -6.2 for b, and 0.61 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-6.2\right)±\sqrt{38.44-4\times 0.61}}{2}
Square -6.2 by squaring both the numerator and the denominator of the fraction.
x=\frac{-\left(-6.2\right)±\sqrt{\frac{961-61}{25}}}{2}
Multiply -4 times 0.61.
x=\frac{-\left(-6.2\right)±\sqrt{36}}{2}
Add 38.44 to -2.44 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-\left(-6.2\right)±6}{2}
Take the square root of 36.
x=\frac{6.2±6}{2}
The opposite of -6.2 is 6.2.
x=\frac{12.2}{2}
Now solve the equation x=\frac{6.2±6}{2} when ± is plus. Add 6.2 to 6.
x=6.1
Divide 12.2 by 2.
x=\frac{0.2}{2}
Now solve the equation x=\frac{6.2±6}{2} when ± is minus. Subtract 6 from 6.2.
x=0.1
Divide 0.2 by 2.
x=6.1 x=0.1
The equation is now solved.
x^{2}-6.2x+0.61=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-6.2x+0.61-0.61=-0.61
Subtract 0.61 from both sides of the equation.
x^{2}-6.2x=-0.61
Subtracting 0.61 from itself leaves 0.
x^{2}-6.2x+\left(-3.1\right)^{2}=-0.61+\left(-3.1\right)^{2}
Divide -6.2, the coefficient of the x term, by 2 to get -3.1. Then add the square of -3.1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-6.2x+9.61=\frac{-61+961}{100}
Square -3.1 by squaring both the numerator and the denominator of the fraction.
x^{2}-6.2x+9.61=9
Add -0.61 to 9.61 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-3.1\right)^{2}=9
Factor x^{2}-6.2x+9.61. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-3.1\right)^{2}}=\sqrt{9}
Take the square root of both sides of the equation.
x-3.1=3 x-3.1=-3
Simplify.
x=6.1 x=0.1
Add 3.1 to both sides of the equation.