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x^{2}-3=0
Multiply 0 and 5 to get 0.
x^{2}=3
Add 3 to both sides. Anything plus zero gives itself.
x=\sqrt{3} x=-\sqrt{3}
Take the square root of both sides of the equation.
x^{2}-3=0
Multiply 0 and 5 to get 0.
x=\frac{0±\sqrt{0^{2}-4\left(-3\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-3\right)}}{2}
Square 0.
x=\frac{0±\sqrt{12}}{2}
Multiply -4 times -3.
x=\frac{0±2\sqrt{3}}{2}
Take the square root of 12.
x=\sqrt{3}
Now solve the equation x=\frac{0±2\sqrt{3}}{2} when ± is plus.
x=-\sqrt{3}
Now solve the equation x=\frac{0±2\sqrt{3}}{2} when ± is minus.
x=\sqrt{3} x=-\sqrt{3}
The equation is now solved.