Solve x^2=432+441

$${ x }^{ 2 } =432+441$$

Solve for x

$$x=3\sqrt{97}\approx 29.546573405$$

$$x=-3\sqrt{97}\approx -29.546573405$$

Steps by Finding Square Root

Add 432 and 441 to get 873.

$$x^{2}=873$$

Take the square root of both sides of the equation.

$$x=3\sqrt{97} x=-3\sqrt{97}$$

Steps Using the Quadratic Formula

Add 432 and 441 to get 873.

$$x^{2}=873$$

Subtract 873 from both sides.

$$x^{2}-873=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -873 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-873\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-873\right)}}{2}$$

Multiply -4 times -873.

$$x=\frac{0±\sqrt{3492}}{2}$$

Take the square root of 3492.

$$x=\frac{0±6\sqrt{97}}{2}$$

Now solve the equation x=\frac{0±6\sqrt{97}}{2} when ± is plus.

$$x=3\sqrt{97}$$

Now solve the equation x=\frac{0±6\sqrt{97}}{2} when ± is minus.

$$x=-3\sqrt{97}$$

The equation is now solved.

$$x=3\sqrt{97} x=-3\sqrt{97}$$