Solve x^2=0.8

$${ x }^{ 2 } =0.8$$

Solve for x

$$x=\frac{2\sqrt{5}}{5}\approx 0.894427191$$

$$x=-\frac{2\sqrt{5}}{5}\approx -0.894427191$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=\frac{2\sqrt{5}}{5} x=-\frac{2\sqrt{5}}{5}$$

Steps Using the Quadratic Formula

Subtract 0.8 from both sides.

$$x^{2}-0.8=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -0.8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-0.8\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-0.8\right)}}{2}$$

Multiply -4 times -0.8.

$$x=\frac{0±\sqrt{3.2}}{2}$$

Take the square root of 3.2.

$$x=\frac{0±\frac{4\sqrt{5}}{5}}{2}$$

Now solve the equation x=\frac{0±\frac{4\sqrt{5}}{5}}{2} when ± is plus.

$$x=\frac{2\sqrt{5}}{5}$$

Now solve the equation x=\frac{0±\frac{4\sqrt{5}}{5}}{2} when ± is minus.

$$x=-\frac{2\sqrt{5}}{5}$$

The equation is now solved.

$$x=\frac{2\sqrt{5}}{5} x=-\frac{2\sqrt{5}}{5}$$