Solve x^2=x^2+x^2/2

$${ x }^{ 2 } = { x }^{ 2 } + \frac{ { x }^{ 2 } }{ 2 }$$

Solve for x

$$x=0$$

Steps by Finding Square Root

Multiply both sides of the equation by 2.

$$2x^{2}=2x^{2}+x^{2}$$

Combine 2x^{2} and x^{2} to get 3x^{2}.

$$2x^{2}=3x^{2}$$

Subtract 3x^{2} from both sides.

$$2x^{2}-3x^{2}=0$$

Combine 2x^{2} and -3x^{2} to get -x^{2}.

$$-x^{2}=0$$

Divide both sides by -1. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

Take the square root of both sides of the equation.

$$x=0 x=0$$

The equation is now solved. Solutions are the same.

$$x=0$$

Steps Using the Quadratic Formula

Multiply both sides of the equation by 2.

$$2x^{2}=2x^{2}+x^{2}$$

Combine 2x^{2} and x^{2} to get 3x^{2}.

$$2x^{2}=3x^{2}$$

Subtract 3x^{2} from both sides.

$$2x^{2}-3x^{2}=0$$

Combine 2x^{2} and -3x^{2} to get -x^{2}.

$$-x^{2}=0$$

Divide both sides by -1. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$x=\frac{0±0}{2}$$

Divide 0 by 2.

$$x=0$$