Solve x^2=left(x-12right)^2

$${ x }^{ 2 } = { \left(x-12 \right) }^{ 2 }$$

Solve for x

$$x=6$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-12\right)^{2}.

$$x^{2}=x^{2}-24x+144$$

Subtract x^{2} from both sides.

$$x^{2}-x^{2}=-24x+144$$

Combine x^{2} and -x^{2} to get 0.

$$0=-24x+144$$

Swap sides so that all variable terms are on the left hand side.

$$-24x+144=0$$

Subtract 144 from both sides. Anything subtracted from zero gives its negation.

$$-24x=-144$$

Divide both sides by -24.

$$x=\frac{-144}{-24}$$

Divide -144 by -24 to get 6.

$$x=6$$