Solve x^2+9=103

$${ x }^{ 2 } +9=103$$

Solve for x

$$x=\sqrt{94}\approx 9.695359715$$

$$x=-\sqrt{94}\approx -9.695359715$$

Steps by Finding Square Root

Subtract 9 from both sides.

$$x^{2}=103-9$$

Subtract 9 from 103 to get 94.

$$x^{2}=94$$

Take the square root of both sides of the equation.

$$x=\sqrt{94} x=-\sqrt{94}$$

Steps Using the Quadratic Formula

Subtract 103 from both sides.

$$x^{2}+9-103=0$$

Subtract 103 from 9 to get -94.

$$x^{2}-94=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -94 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-94\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-94\right)}}{2}$$

Multiply -4 times -94.

$$x=\frac{0±\sqrt{376}}{2}$$

Take the square root of 376.

$$x=\frac{0±2\sqrt{94}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{94}}{2} when ± is plus.

$$x=\sqrt{94}$$

Now solve the equation x=\frac{0±2\sqrt{94}}{2} when ± is minus.

$$x=-\sqrt{94}$$

The equation is now solved.

$$x=\sqrt{94} x=-\sqrt{94}$$