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x^{2}+8x=2400
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x^{2}+8x-2400=2400-2400
Subtract 2400 from both sides of the equation.
x^{2}+8x-2400=0
Subtracting 2400 from itself leaves 0.
x=\frac{-8±\sqrt{8^{2}-4\left(-2400\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 8 for b, and -2400 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-8±\sqrt{64-4\left(-2400\right)}}{2}
Square 8.
x=\frac{-8±\sqrt{64+9600}}{2}
Multiply -4 times -2400.
x=\frac{-8±\sqrt{9664}}{2}
Add 64 to 9600.
x=\frac{-8±8\sqrt{151}}{2}
Take the square root of 9664.
x=\frac{8\sqrt{151}-8}{2}
Now solve the equation x=\frac{-8±8\sqrt{151}}{2} when ± is plus. Add -8 to 8\sqrt{151}.
x=4\sqrt{151}-4
Divide -8+8\sqrt{151} by 2.
x=\frac{-8\sqrt{151}-8}{2}
Now solve the equation x=\frac{-8±8\sqrt{151}}{2} when ± is minus. Subtract 8\sqrt{151} from -8.
x=-4\sqrt{151}-4
Divide -8-8\sqrt{151} by 2.
x=4\sqrt{151}-4 x=-4\sqrt{151}-4
The equation is now solved.
x^{2}+8x=2400
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+8x+4^{2}=2400+4^{2}
Divide 8, the coefficient of the x term, by 2 to get 4. Then add the square of 4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+8x+16=2400+16
Square 4.
x^{2}+8x+16=2416
Add 2400 to 16.
\left(x+4\right)^{2}=2416
Factor x^{2}+8x+16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+4\right)^{2}}=\sqrt{2416}
Take the square root of both sides of the equation.
x+4=4\sqrt{151} x+4=-4\sqrt{151}
Simplify.
x=4\sqrt{151}-4 x=-4\sqrt{151}-4
Subtract 4 from both sides of the equation.