Solve x^2+49=0

$${ x }^{ 2 } +49 = 0$$

Solve for x (complex solution)

$$x=-7i$$

$$x=7i$$

Steps by Finding Square Root

Subtract 49 from both sides. Anything subtracted from zero gives its negation.

$$x^{2}=-49$$

The equation is now solved.

$$x=7i x=-7i$$

Steps Using the Quadratic Formula

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$x^{2}+49=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 49 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 49}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 49}}{2}$$

Multiply -4 times 49.

$$x=\frac{0±\sqrt{-196}}{2}$$

Take the square root of -196.

$$x=\frac{0±14i}{2}$$

Now solve the equation x=\frac{0±14i}{2} when ± is plus.

$$x=7i$$

Now solve the equation x=\frac{0±14i}{2} when ± is minus.

$$x=-7i$$

The equation is now solved.

$$x=7i x=-7i$$