Solve x^2+489x+28980=0

$${ x }^{ 2 } +489x+28980 = 0$$

Solve for x

$$x=-420$$

$$x=-69$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x^{2}+489x+28980=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 489 for b, and 28980 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-489±\sqrt{489^{2}-4\times 28980}}{2}$$

Square 489.

$$x=\frac{-489±\sqrt{239121-4\times 28980}}{2}$$

Multiply -4 times 28980.

$$x=\frac{-489±\sqrt{239121-115920}}{2}$$

Add 239121 to -115920.

$$x=\frac{-489±\sqrt{123201}}{2}$$

Take the square root of 123201.

$$x=\frac{-489±351}{2}$$

Now solve the equation x=\frac{-489±351}{2} when ± is plus. Add -489 to 351.

$$x=-\frac{138}{2}$$

Divide -138 by 2.

$$x=-69$$

Now solve the equation x=\frac{-489±351}{2} when ± is minus. Subtract 351 from -489.

$$x=-\frac{840}{2}$$

Divide -840 by 2.

$$x=-420$$

The equation is now solved.

$$x=-69 x=-420$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$x^{2}+489x+28980=0$$

Subtract 28980 from both sides of the equation.

$$x^{2}+489x+28980-28980=-28980$$

Subtracting 28980 from itself leaves 0.

$$x^{2}+489x=-28980$$

Divide 489, the coefficient of the x term, by 2 to get \frac{489}{2}. Then add the square of \frac{489}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+489x+\left(\frac{489}{2}\right)^{2}=-28980+\left(\frac{489}{2}\right)^{2}$$

Square \frac{489}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}+489x+\frac{239121}{4}=-28980+\frac{239121}{4}$$

Add -28980 to \frac{239121}{4}.

$$x^{2}+489x+\frac{239121}{4}=\frac{123201}{4}$$

Factor x^{2}+489x+\frac{239121}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{489}{2}\right)^{2}=\frac{123201}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+\frac{489}{2}\right)^{2}}=\sqrt{\frac{123201}{4}}$$

Simplify.

$$x+\frac{489}{2}=\frac{351}{2} x+\frac{489}{2}=-\frac{351}{2}$$

Subtract \frac{489}{2} from both sides of the equation.

$$x=-69 x=-420$$