Solve x^2+3x-934=97

$${ x }^{ 2 } +3x-934=97$$

Solve for x

$$x = \frac{\sqrt{4133} - 3}{2} \approx 30.644206321$$

$$x=\frac{-\sqrt{4133}-3}{2}\approx -33.644206321$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x^{2}+3x-934=97$$

Subtract 97 from both sides of the equation.

$$x^{2}+3x-934-97=97-97$$

Subtracting 97 from itself leaves 0.

$$x^{2}+3x-934-97=0$$

Subtract 97 from -934.

$$x^{2}+3x-1031=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 3 for b, and -1031 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-3±\sqrt{3^{2}-4\left(-1031\right)}}{2}$$

Square 3.

$$x=\frac{-3±\sqrt{9-4\left(-1031\right)}}{2}$$

Multiply -4 times -1031.

$$x=\frac{-3±\sqrt{9+4124}}{2}$$

Add 9 to 4124.

$$x=\frac{-3±\sqrt{4133}}{2}$$

Now solve the equation x=\frac{-3±\sqrt{4133}}{2} when ± is plus. Add -3 to \sqrt{4133}.

$$x=\frac{\sqrt{4133}-3}{2}$$

Now solve the equation x=\frac{-3±\sqrt{4133}}{2} when ± is minus. Subtract \sqrt{4133} from -3.

$$x=\frac{-\sqrt{4133}-3}{2}$$

The equation is now solved.

$$x=\frac{\sqrt{4133}-3}{2} x=\frac{-\sqrt{4133}-3}{2}$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$x^{2}+3x-934=97$$

Add 934 to both sides of the equation.

$$x^{2}+3x-934-\left(-934\right)=97-\left(-934\right)$$

Subtracting -934 from itself leaves 0.

$$x^{2}+3x=97-\left(-934\right)$$

Subtract -934 from 97.

$$x^{2}+3x=1031$$

Divide 3, the coefficient of the x term, by 2 to get \frac{3}{2}. Then add the square of \frac{3}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+3x+\left(\frac{3}{2}\right)^{2}=1031+\left(\frac{3}{2}\right)^{2}$$

Square \frac{3}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}+3x+\frac{9}{4}=1031+\frac{9}{4}$$

Add 1031 to \frac{9}{4}.

$$x^{2}+3x+\frac{9}{4}=\frac{4133}{4}$$

Factor x^{2}+3x+\frac{9}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{3}{2}\right)^{2}=\frac{4133}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+\frac{3}{2}\right)^{2}}=\sqrt{\frac{4133}{4}}$$

Simplify.

$$x+\frac{3}{2}=\frac{\sqrt{4133}}{2} x+\frac{3}{2}=-\frac{\sqrt{4133}}{2}$$

Subtract \frac{3}{2} from both sides of the equation.

$$x=\frac{\sqrt{4133}-3}{2} x=\frac{-\sqrt{4133}-3}{2}$$