Solve x^2+25-C=8

$${ x }^{ 2 } +25-C = 8$$

Solve for C

$$C=x^{2}+17$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$25-C=8-x^{2}$$

Subtract 25 from both sides.

$$-C=8-x^{2}-25$$

Subtract 25 from 8 to get -17.

$$-C=-17-x^{2}$$

The equation is in standard form.

$$-C=-x^{2}-17$$

Divide both sides by -1.

$$\frac{-C}{-1}=\frac{-x^{2}-17}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$C=\frac{-x^{2}-17}{-1}$$

Divide -17-x^{2} by -1.

$$C=x^{2}+17$$

Solve for x (complex solution)

$$x=-\sqrt{C-17}$$

$$x=\sqrt{C-17}$$

Solve for x

$$x=\sqrt{C-17}$$

$$x=-\sqrt{C-17}\text{, }C\geq 17$$