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Solve for x (complex solution)
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x^{2}+24x+85=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-24±\sqrt{24^{2}-4\times 85}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 24 for b, and 85 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-24±\sqrt{576-4\times 85}}{2}
Square 24.
x=\frac{-24±\sqrt{576-340}}{2}
Multiply -4 times 85.
x=\frac{-24±\sqrt{236}}{2}
Add 576 to -340.
x=\frac{-24±2\sqrt{59}}{2}
Take the square root of 236.
x=\frac{2\sqrt{59}-24}{2}
Now solve the equation x=\frac{-24±2\sqrt{59}}{2} when ± is plus. Add -24 to 2\sqrt{59}.
x=\sqrt{59}-12
Divide -24+2\sqrt{59} by 2.
x=\frac{-2\sqrt{59}-24}{2}
Now solve the equation x=\frac{-24±2\sqrt{59}}{2} when ± is minus. Subtract 2\sqrt{59} from -24.
x=-\sqrt{59}-12
Divide -24-2\sqrt{59} by 2.
x=\sqrt{59}-12 x=-\sqrt{59}-12
The equation is now solved.
x^{2}+24x+85=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+24x+85-85=-85
Subtract 85 from both sides of the equation.
x^{2}+24x=-85
Subtracting 85 from itself leaves 0.
x^{2}+24x+12^{2}=-85+12^{2}
Divide 24, the coefficient of the x term, by 2 to get 12. Then add the square of 12 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+24x+144=-85+144
Square 12.
x^{2}+24x+144=59
Add -85 to 144.
\left(x+12\right)^{2}=59
Factor x^{2}+24x+144. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+12\right)^{2}}=\sqrt{59}
Take the square root of both sides of the equation.
x+12=\sqrt{59} x+12=-\sqrt{59}
Simplify.
x=\sqrt{59}-12 x=-\sqrt{59}-12
Subtract 12 from both sides of the equation.
x^{2}+24x+85=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-24±\sqrt{24^{2}-4\times 85}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 24 for b, and 85 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-24±\sqrt{576-4\times 85}}{2}
Square 24.
x=\frac{-24±\sqrt{576-340}}{2}
Multiply -4 times 85.
x=\frac{-24±\sqrt{236}}{2}
Add 576 to -340.
x=\frac{-24±2\sqrt{59}}{2}
Take the square root of 236.
x=\frac{2\sqrt{59}-24}{2}
Now solve the equation x=\frac{-24±2\sqrt{59}}{2} when ± is plus. Add -24 to 2\sqrt{59}.
x=\sqrt{59}-12
Divide -24+2\sqrt{59} by 2.
x=\frac{-2\sqrt{59}-24}{2}
Now solve the equation x=\frac{-24±2\sqrt{59}}{2} when ± is minus. Subtract 2\sqrt{59} from -24.
x=-\sqrt{59}-12
Divide -24-2\sqrt{59} by 2.
x=\sqrt{59}-12 x=-\sqrt{59}-12
The equation is now solved.
x^{2}+24x+85=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+24x+85-85=-85
Subtract 85 from both sides of the equation.
x^{2}+24x=-85
Subtracting 85 from itself leaves 0.
x^{2}+24x+12^{2}=-85+12^{2}
Divide 24, the coefficient of the x term, by 2 to get 12. Then add the square of 12 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+24x+144=-85+144
Square 12.
x^{2}+24x+144=59
Add -85 to 144.
\left(x+12\right)^{2}=59
Factor x^{2}+24x+144. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+12\right)^{2}}=\sqrt{59}
Take the square root of both sides of the equation.
x+12=\sqrt{59} x+12=-\sqrt{59}
Simplify.
x=\sqrt{59}-12 x=-\sqrt{59}-12
Subtract 12 from both sides of the equation.