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x^{2}+4=\left(8-x\right)^{2}
Calculate 2 to the power of 2 and get 4.
x^{2}+4=64-16x+x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(8-x\right)^{2}.
x^{2}+4+16x=64+x^{2}
Add 16x to both sides.
x^{2}+4+16x-x^{2}=64
Subtract x^{2} from both sides.
4+16x=64
Combine x^{2} and -x^{2} to get 0.
16x=64-4
Subtract 4 from both sides.
16x=60
Subtract 4 from 64 to get 60.
x=\frac{60}{16}
Divide both sides by 16.
x=\frac{15}{4}
Reduce the fraction \frac{60}{16} to lowest terms by extracting and canceling out 4.