Solve 9^3*3-3^2*2+3^2div9-5^3*{3}^2-{29}^2-10

$${ 9 }^{ 3 } \times 3- { 3 }^{ 2 } \times 2+ { 3 }^{ 2 } \div 9- { 5 }^{ 3 } \times { 3 }^{ 2 } - { 29 }^{ 2 } -10$$

Evaluate

$$194$$

Solution Steps

Calculate 9 to the power of 3 and get 729.

$$729\times 3-3^{2}\times 2+\frac{3^{2}}{9}-5^{3}\times 3^{2}-29^{2}-10$$

Multiply 729 and 3 to get 2187.

$$2187-3^{2}\times 2+\frac{3^{2}}{9}-5^{3}\times 3^{2}-29^{2}-10$$

Calculate 3 to the power of 2 and get 9.

$$2187-9\times 2+\frac{3^{2}}{9}-5^{3}\times 3^{2}-29^{2}-10$$

Multiply 9 and 2 to get 18.

$$2187-18+\frac{3^{2}}{9}-5^{3}\times 3^{2}-29^{2}-10$$

Subtract 18 from 2187 to get 2169.

$$2169+\frac{3^{2}}{9}-5^{3}\times 3^{2}-29^{2}-10$$

Calculate 3 to the power of 2 and get 9.

$$2169+\frac{9}{9}-5^{3}\times 3^{2}-29^{2}-10$$

Divide 9 by 9 to get 1.

$$2169+1-5^{3}\times 3^{2}-29^{2}-10$$

Add 2169 and 1 to get 2170.

$$2170-5^{3}\times 3^{2}-29^{2}-10$$

Calculate 5 to the power of 3 and get 125.

$$2170-125\times 3^{2}-29^{2}-10$$

Calculate 3 to the power of 2 and get 9.

$$2170-125\times 9-29^{2}-10$$

Multiply 125 and 9 to get 1125.

$$2170-1125-29^{2}-10$$

Subtract 1125 from 2170 to get 1045.

$$1045-29^{2}-10$$

Calculate 29 to the power of 2 and get 841.

$$1045-841-10$$

Subtract 841 from 1045 to get 204.

$$204-10$$

Subtract 10 from 204 to get 194.

$$194$$

Factor

$$2\times 97$$